Pressure is the single topic that causes more lost marks in the Level 2 scientific principles exam than any other. Not because it's genuinely difficult — but because the maths looks intimidating, the units are easy to mix up, and examiners know exactly which mistakes to build their distractors around.

This post walks through everything you need to know for the Level 2 exam: head pressure, units, the pressure formula, the force formula, and the traps examiners reliably set. At the end there's a 10-question mock test with full explanations — treat it as a diagnostic for where you stand right now.

If you want the wider revision strategy rather than just the science, pair this with the spaced repetition guide and the common exam mistakes post.

What pressure actually is

Pressure is force spread over an area. The formal definition is:

Beaker of liquid illustrating that pressure exerted by a liquid acts in all directions and depends on depth

Pressure = Force ÷ Area

The SI unit is the pascal (Pa), where 1 pascal equals 1 newton per square metre. That's a tiny amount of pressure, so plumbing uses larger units in practice:

The conversions you need to know cold:

To convert any of these into bar:

Exam questions routinely switch units between the question stem and the answer options — a calculation given in kPa with answers offered in bar, for example. This is one of the most reliable places students lose marks: the arithmetic is right, the answer is correct in one unit, but the selected option is in the wrong one.

Head pressure: the plumbing shortcut

In plumbing, we're almost always calculating pressure produced by a column of water. There's a shortcut that saves you from doing the full formula every time:

Pumping station feeding a raised storage tank with the static head marked between the water level and the outlet

For every 1 metre of vertical height (head), water produces approximately 0.1 bar of pressure.

So a cold water storage cistern 5 metres above a bathroom basin produces roughly 0.5 bar at the basin tap. A header tank 10 metres up produces about 1 bar.

Technically this is an approximation — the exact figure is closer to 0.0981 bar per metre — but 0.1 bar per metre is the working rule of thumb used throughout the trade. Memorise this one. It turns up directly in exam questions as a fast shortcut, and it's genuinely useful on site — when a customer is complaining about slow flow to their bathroom and you need to estimate the head from their loft cistern in your head, the 0.1-bar-per-metre rule is how you do it. This is one of the rare bits of Level 2 theory that earns its keep every day of your career.

The pressure formula: P = ρgh

For precise calculations, use the full formula:

Cold water cistern feeding a 15mm tap with the head height labelled, used to calculate the pressure at the tap inlet

P = ρ × g × h

Where:

So the pressure at the base of a 6-metre column of water is:

P = 1,000 × 9.81 × 6 = 58,860 Pa (about 0.59 bar)

The units matter. Density in kg/m³, gravity in m/s², height in metres — anything else and your answer comes out in the wrong units.

Force vs pressure: don't confuse them

Pressure and force are related but not the same thing. Pressure is force per unit of area; force is what that pressure exerts on a given surface.

Force = Pressure × Area (F = P × A)

Where force is in newtons (N), pressure in pascals (Pa), and area in square metres (m²).

A classic exam question: "A pressure of 500 Pa is applied to an area of 2 m². What is the force?"

F = 500 × 2 = 1,000 N

This is where unit discipline really matters. If the question gives you pressure in kPa or bar, convert to pascals before multiplying. If the area is in cm² or mm², convert to square metres.

Tensile, compressive and shear force

Force can act on a body in three different ways. Plumbers see all three: in pipework supports, in fixings, and in the materials that pipes and fittings are made from. Each one is named after the way the force is applied.

Compressive force

Diagram of a block with arrows pushing inward from either side, illustrating compressive force squeezing a body

Compressive force acts inwards, squeezing the body. Examples: the weight of stored water pressing down on the base of a cistern; the load on a vertical post supporting a tank in the loft; the clamping force on an olive in a compression fitting. Materials that resist compression well include cast iron, concrete and dense masonry — they can carry heavy weight without crushing.

Tensile force

Diagram of a block with arrows pulling outward on either side, illustrating tensile force stretching a body

Tensile force acts outwards, pulling a body apart. Example: a hanging bracket holding a length of pipe — gravity is pulling the pipe downwards and the bracket and its fixing are in tension, resisting that pull. Steel cables, threaded rod, and most ductile metals carry tensile loads well. Cast iron is poor in tension — it will snap rather than stretch.

Shear force

Diagram of a block with parallel arrows acting in opposite directions, illustrating shear force sliding two parts of a body across each other

Shear force acts parallel to a surface, with two opposite forces sliding across each other. Example: a screw fixing a pipe clip to a joist — if the pipe tries to drop, it puts a shear load on the screw across the joist face. Bolts, pins and rivets are the components that typically resist shear loading.

The three most common exam traps

Trap 1: Unit swapping. The commonest distractor is a correct number in the wrong unit. If the question asks for pascals and you've calculated in bar, your arithmetic is right but your answer is wrong.

Trap 2: Forgetting the density. In a P = ρgh question, students often drop the density from the formula and write P = gh. Check every formula before you hit the calculator.

Trap 3: Mixing up pressure and force. If a question gives you an area, stop and ask: is it asking for pressure (divide) or force (multiply)? This alone catches a surprising number of students.

Quick revision summary

Before the mock test, five things you need to be able to produce from memory:

  1. Pressure = Force ÷ Area (units: pascals = newtons per square metre)
  2. 1 bar = 100,000 Pa = 100 kPa = 0.1 MPa (and therefore 1 MPa = 10 bar)
  3. Approximately 0.1 bar of pressure per metre of head
  4. P = ρ × g × h (with ρ = 1,000 kg/m³ for water, g = 9.81 m/s²)
  5. F = P × A (with pressure in Pa and area in m²)

📝 10-Question Mock Test

Click an option to see whether you got it right. Explanations appear instantly — no submitting at the end.

Your score: 0 / 10
Question 1 of 10
What is the approximate pressure at the base of a 10-metre head of water?
Question 2 of 10
1 bar is equivalent to:
Question 3 of 10
In the formula P = ρgh, what does ρ (rho) represent?
Question 4 of 10
A cold water storage cistern is 5 metres above a bathroom basin tap. What is the approximate static pressure at the tap?
Question 5 of 10
What is standard atmospheric pressure at sea level?
Question 6 of 10
A pressure of 500 Pa is applied to an area of 2 m². What is the resulting force?
Question 7 of 10
What is the pressure (to the nearest whole number) at the base of a 4-metre water column? Use density of water = 1,000 kg/m³ and g = 9.81 m/s².
Question 8 of 10
A force of 2,000 N is applied to an area of 0.5 m². What is the pressure?
Question 9 of 10
In an indirect cold water system, why is the pressure at a bathroom basin tap typically lower than at the kitchen tap?
Question 10 of 10
Two basin taps in the same house are fed from the same cold water storage cistern. One is 2 metres below the cistern; the other is 4 metres below. Which statement is correct?

How PlumbMate puts this into practice

Questions like these are exactly what PlumbMate drills you on — but with the spaced repetition engine doing the scheduling so you're not retesting yourself on the stuff you already know.